6(2f+7)=3-f

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Solution for 6(2f+7)=3-f equation: 



6(2f+7)=3-f

We move all terms to the left:

6(2f+7)-(3-f)=0

We add all the numbers together, and all the variables

6(2f+7)-(-1f+3)=0

We multiply parentheses

12f-(-1f+3)+42=0

We get rid of parentheses

12f+1f-3+42=0

We add all the numbers together, and all the variables

13f+39=0

We move all terms containing f to the left, all other terms to the right

13f=-39

f=-39/13

f=-3

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