6(2g+2)-5g=3(4g-5)-3

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Solution for 6(2g+2)-5g=3(4g-5)-3 equation: 



6(2g+2)-5g=3(4g-5)-3

We move all terms to the left:

6(2g+2)-5g-(3(4g-5)-3)=0

We add all the numbers together, and all the variables

-5g+6(2g+2)-(3(4g-5)-3)=0

We multiply parentheses

-5g+12g-(3(4g-5)-3)+12=0



We calculate terms in parentheses: -(3(4g-5)-3), so:

3(4g-5)-3

We multiply parentheses

12g-15-3

We add all the numbers together, and all the variables

12g-18

Back to the equation:

-(12g-18)



We add all the numbers together, and all the variables

7g-(12g-18)+12=0

We get rid of parentheses

7g-12g+18+12=0

We add all the numbers together, and all the variables

-5g+30=0

We move all terms containing g to the left, all other terms to the right

-5g=-30

g=-30/-5

g=+6

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