6(2h-7)=3(5h-4)

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Solution for 6(2h-7)=3(5h-4) equation: 



6(2h-7)=3(5h-4)

We move all terms to the left:

6(2h-7)-(3(5h-4))=0

We multiply parentheses

12h-(3(5h-4))-42=0



We calculate terms in parentheses: -(3(5h-4)), so:

3(5h-4)

We multiply parentheses

15h-12

Back to the equation:

-(15h-12)



We get rid of parentheses

12h-15h+12-42=0

We add all the numbers together, and all the variables

-3h-30=0

We move all terms containing h to the left, all other terms to the right

-3h=30

h=30/-3

h=-10

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