6(2i+4)=2(3i+6)

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Solution for 6(2i+4)=2(3i+6) equation: 



6(2i+4)=2(3i+6)

We move all terms to the left:

6(2i+4)-(2(3i+6))=0

We multiply parentheses

12i-(2(3i+6))+24=0



We calculate terms in parentheses: -(2(3i+6)), so:

2(3i+6)

We multiply parentheses

6i+12

Back to the equation:

-(6i+12)



We get rid of parentheses

12i-6i-12+24=0

We add all the numbers together, and all the variables

6i+12=0

We move all terms containing i to the left, all other terms to the right

6i=-12

i=-12/6

i=-2

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