6(2j+1)-5=7j+2(j-1)

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Solution for 6(2j+1)-5=7j+2(j-1) equation:


Simplifying
6(2j + 1) + -5 = 7j + 2(j + -1)

Reorder the terms:
6(1 + 2j) + -5 = 7j + 2(j + -1)
(1 * 6 + 2j * 6) + -5 = 7j + 2(j + -1)
(6 + 12j) + -5 = 7j + 2(j + -1)

Reorder the terms:
6 + -5 + 12j = 7j + 2(j + -1)

Combine like terms: 6 + -5 = 1
1 + 12j = 7j + 2(j + -1)

Reorder the terms:
1 + 12j = 7j + 2(-1 + j)
1 + 12j = 7j + (-1 * 2 + j * 2)
1 + 12j = 7j + (-2 + 2j)

Reorder the terms:
1 + 12j = -2 + 7j + 2j

Combine like terms: 7j + 2j = 9j
1 + 12j = -2 + 9j

Solving
1 + 12j = -2 + 9j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-9j' to each side of the equation.
1 + 12j + -9j = -2 + 9j + -9j

Combine like terms: 12j + -9j = 3j
1 + 3j = -2 + 9j + -9j

Combine like terms: 9j + -9j = 0
1 + 3j = -2 + 0
1 + 3j = -2

Add '-1' to each side of the equation.
1 + -1 + 3j = -2 + -1

Combine like terms: 1 + -1 = 0
0 + 3j = -2 + -1
3j = -2 + -1

Combine like terms: -2 + -1 = -3
3j = -3

Divide each side by '3'.
j = -1

Simplifying
j = -1

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