6(2k+2)=-4(k+5)

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Solution for 6(2k+2)=-4(k+5) equation: 



6(2k+2)=-4(k+5)

We move all terms to the left:

6(2k+2)-(-4(k+5))=0

We multiply parentheses

12k-(-4(k+5))+12=0



We calculate terms in parentheses: -(-4(k+5)), so:

-4(k+5)

We multiply parentheses

-4k-20

Back to the equation:

-(-4k-20)



We get rid of parentheses

12k+4k+20+12=0

We add all the numbers together, and all the variables

16k+32=0

We move all terms containing k to the left, all other terms to the right

16k=-32

k=-32/16

k=-2

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