6(2k-7)+8=9k-16

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Solution for 6(2k-7)+8=9k-16 equation: 



6(2k-7)+8=9k-16

We move all terms to the left:

6(2k-7)+8-(9k-16)=0

We multiply parentheses

12k-(9k-16)-42+8=0

We get rid of parentheses

12k-9k+16-42+8=0

We add all the numbers together, and all the variables

3k-18=0

We move all terms containing k to the left, all other terms to the right

3k=18

k=18/3

k=6

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