6(2l+10)=108

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Solution for 6(2l+10)=108 equation: 



6(2l+10)=108

We move all terms to the left:

6(2l+10)-(108)=0

We multiply parentheses

12l+60-108=0

We add all the numbers together, and all the variables

12l-48=0

We move all terms containing l to the left, all other terms to the right

12l=48

l=48/12

l=4

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