6(2l+10)=132

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Solution for 6(2l+10)=132 equation: 



6(2l+10)=132

We move all terms to the left:

6(2l+10)-(132)=0

We multiply parentheses

12l+60-132=0

We add all the numbers together, and all the variables

12l-72=0

We move all terms containing l to the left, all other terms to the right

12l=72

l=72/12

l=6

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