6(2l+3)=5(-4l+2)

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Solution for 6(2l+3)=5(-4l+2) equation: 



6(2l+3)=5(-4l+2)

We move all terms to the left:

6(2l+3)-(5(-4l+2))=0

We multiply parentheses

12l-(5(-4l+2))+18=0



We calculate terms in parentheses: -(5(-4l+2)), so:

5(-4l+2)

We multiply parentheses

-20l+10

Back to the equation:

-(-20l+10)



We get rid of parentheses

12l+20l-10+18=0

We add all the numbers together, and all the variables

32l+8=0

We move all terms containing l to the left, all other terms to the right

32l=-8

l=-8/32

l=-1/4

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