6(2l+3)=78

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Solution for 6(2l+3)=78 equation: 



6(2l+3)=78

We move all terms to the left:

6(2l+3)-(78)=0

We multiply parentheses

12l+18-78=0

We add all the numbers together, and all the variables

12l-60=0

We move all terms containing l to the left, all other terms to the right

12l=60

l=60/12

l=5

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