6(2m+1)+2(1-2m)=m-1+6m-5

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Solution for 6(2m+1)+2(1-2m)=m-1+6m-5 equation: 



6(2m+1)+2(1-2m)=m-1+6m-5

We move all terms to the left:

6(2m+1)+2(1-2m)-(m-1+6m-5)=0

We add all the numbers together, and all the variables

6(2m+1)+2(-2m+1)-(7m-6)=0

We multiply parentheses

12m-4m-(7m-6)+6+2=0

We get rid of parentheses

12m-4m-7m+6+6+2=0

We add all the numbers together, and all the variables

m+14=0

We move all terms containing m to the left, all other terms to the right

m=-14

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