6(2m+1)=2(24-m)

Solution for 6(2m+1)=2(24-m) equation:

6(2m+1)=2(24-m)

We move all terms to the left:

6(2m+1)-(2(24-m))=0

We add all the numbers together, and all the variables

6(2m+1)-(2(-1m+24))=0

We multiply parentheses

12m-(2(-1m+24))+6=0


We calculate terms in parentheses: -(2(-1m+24)), so:

2(-1m+24)

We multiply parentheses

-2m+48

Back to the equation:

-(-2m+48)


We get rid of parentheses

12m+2m-48+6=0

We add all the numbers together, and all the variables

14m-42=0

We move all terms containing m to the left, all other terms to the right

14m=42

m=42/14

m=3