6(2m+3)=-2(-2m+7)

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Solution for 6(2m+3)=-2(-2m+7) equation: 



6(2m+3)=-2(-2m+7)

We move all terms to the left:

6(2m+3)-(-2(-2m+7))=0

We multiply parentheses

12m-(-2(-2m+7))+18=0



We calculate terms in parentheses: -(-2(-2m+7)), so:

-2(-2m+7)

We multiply parentheses

4m-14

Back to the equation:

-(4m-14)



We get rid of parentheses

12m-4m+14+18=0

We add all the numbers together, and all the variables

8m+32=0

We move all terms containing m to the left, all other terms to the right

8m=-32

m=-32/8

m=-4

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