6(2m+3)=13m+19

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Solution for 6(2m+3)=13m+19 equation: 



6(2m+3)=13m+19

We move all terms to the left:

6(2m+3)-(13m+19)=0

We multiply parentheses

12m-(13m+19)+18=0

We get rid of parentheses

12m-13m-19+18=0

We add all the numbers together, and all the variables

-1m-1=0

We move all terms containing m to the left, all other terms to the right

-m=1

m=1/-1

m=-1

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