6(2m+3n-5)+41=

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Solution for 6(2m+3n-5)+41= equation:


Simplifying
6(2m + 3n + -5) + 41 = 0

Reorder the terms:
6(-5 + 2m + 3n) + 41 = 0
(-5 * 6 + 2m * 6 + 3n * 6) + 41 = 0
(-30 + 12m + 18n) + 41 = 0

Reorder the terms:
-30 + 41 + 12m + 18n = 0

Combine like terms: -30 + 41 = 11
11 + 12m + 18n = 0

Solving
11 + 12m + 18n = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + 12m + -11 + 18n = 0 + -11

Reorder the terms:
11 + -11 + 12m + 18n = 0 + -11

Combine like terms: 11 + -11 = 0
0 + 12m + 18n = 0 + -11
12m + 18n = 0 + -11

Combine like terms: 0 + -11 = -11
12m + 18n = -11

Add '-18n' to each side of the equation.
12m + 18n + -18n = -11 + -18n

Combine like terms: 18n + -18n = 0
12m + 0 = -11 + -18n
12m = -11 + -18n

Divide each side by '12'.
m = -0.9166666667 + -1.5n

Simplifying
m = -0.9166666667 + -1.5n

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