6(2m-1)(3m+4)=0

Solution for 6(2m-1)(3m+4)=0 equation:

6(2m-1)(3m+4)=0

We multiply parentheses ..

6(+6m^2+8m-3m-4)=0

We multiply parentheses

36m^2+48m-18m-24=0

We add all the numbers together, and all the variables

36m^2+30m-24=0

a = 36; b = 30; c = -24;
Δ = b2-4ac
Δ = 302-4·36·(-24)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-66}{2*36}=\frac{-96}{72}
=-1+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+66}{2*36}=\frac{36}{72}
=1/2
$