6(2m-10)+3(-3m-2)=-120

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Solution for 6(2m-10)+3(-3m-2)=-120 equation: 



6(2m-10)+3(-3m-2)=-120

We move all terms to the left:

6(2m-10)+3(-3m-2)-(-120)=0

We add all the numbers together, and all the variables

6(2m-10)+3(-3m-2)+120=0

We multiply parentheses

12m-9m-60-6+120=0

We add all the numbers together, and all the variables

3m+54=0

We move all terms containing m to the left, all other terms to the right

3m=-54

m=-54/3

m=-18

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