6(2n)+3(r+2)=

Solution for 6(2n)+3(r+2)= equation:

Simplifying
6(2n) + 3(r + 2) = 0

Remove parenthesis around (2n)
6 * 2n + 3(r + 2) = 0

Multiply 6 * 2
12n + 3(r + 2) = 0

Reorder the terms:
12n + 3(2 + r) = 0
12n + (2 * 3 + r * 3) = 0
12n + (6 + 3r) = 0

Reorder the terms:
6 + 12n + 3r = 0

Solving
6 + 12n + 3r = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 12n + -6 + 3r = 0 + -6

Reorder the terms:
6 + -6 + 12n + 3r = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 12n + 3r = 0 + -6
12n + 3r = 0 + -6

Combine like terms: 0 + -6 = -6
12n + 3r = -6

Add '-3r' to each side of the equation.
12n + 3r + -3r = -6 + -3r

Combine like terms: 3r + -3r = 0
12n + 0 = -6 + -3r
12n = -6 + -3r

Divide each side by '12'.
n = -0.5 + -0.25r

Simplifying
n = -0.5 + -0.25r