6(2n+1)=7(7n+3)+8

Solution for 6(2n+1)=7(7n+3)+8 equation:

6(2n+1)=7(7n+3)+8

We move all terms to the left:

6(2n+1)-(7(7n+3)+8)=0

We multiply parentheses

12n-(7(7n+3)+8)+6=0


We calculate terms in parentheses: -(7(7n+3)+8), so:

7(7n+3)+8

We multiply parentheses

49n+21+8

We add all the numbers together, and all the variables

49n+29

Back to the equation:

-(49n+29)


We get rid of parentheses

12n-49n-29+6=0

We add all the numbers together, and all the variables

-37n-23=0

We move all terms containing n to the left, all other terms to the right

-37n=23

n=23/-37

n=-23/37