6(2n+1)=7(8n+3)=3

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Solution for 6(2n+1)=7(8n+3)=3 equation: 



6(2n+1)=7(8n+3)=3

We move all terms to the left:

6(2n+1)-(7(8n+3))=0

We multiply parentheses

12n-(7(8n+3))+6=0



We calculate terms in parentheses: -(7(8n+3)), so:

7(8n+3)

We multiply parentheses

56n+21

Back to the equation:

-(56n+21)



We get rid of parentheses

12n-56n-21+6=0

We add all the numbers together, and all the variables

-44n-15=0

We move all terms containing n to the left, all other terms to the right

-44n=15

n=15/-44

n=-15/44

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