6(2n+1)=9(3n+7)+3

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Solution for 6(2n+1)=9(3n+7)+3 equation:



6(2n+1)=9(3n+7)+3
We move all terms to the left:
6(2n+1)-(9(3n+7)+3)=0
We multiply parentheses
12n-(9(3n+7)+3)+6=0
We calculate terms in parentheses: -(9(3n+7)+3), so:
9(3n+7)+3
We multiply parentheses
27n+63+3
We add all the numbers together, and all the variables
27n+66
Back to the equation:
-(27n+66)
We get rid of parentheses
12n-27n-66+6=0
We add all the numbers together, and all the variables
-15n-60=0
We move all terms containing n to the left, all other terms to the right
-15n=60
n=60/-15
n=-4

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