6(2n+2)=9(9n+3)+5

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Solution for 6(2n+2)=9(9n+3)+5 equation: 



6(2n+2)=9(9n+3)+5

We move all terms to the left:

6(2n+2)-(9(9n+3)+5)=0

We multiply parentheses

12n-(9(9n+3)+5)+12=0



We calculate terms in parentheses: -(9(9n+3)+5), so:

9(9n+3)+5

We multiply parentheses

81n+27+5

We add all the numbers together, and all the variables

81n+32

Back to the equation:

-(81n+32)



We get rid of parentheses

12n-81n-32+12=0

We add all the numbers together, and all the variables

-69n-20=0

We move all terms containing n to the left, all other terms to the right

-69n=20

n=20/-69

n=-20/69

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