6(2n+3)=9(7n+1)+5

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Solution for 6(2n+3)=9(7n+1)+5 equation: 



6(2n+3)=9(7n+1)+5

We move all terms to the left:

6(2n+3)-(9(7n+1)+5)=0

We multiply parentheses

12n-(9(7n+1)+5)+18=0



We calculate terms in parentheses: -(9(7n+1)+5), so:

9(7n+1)+5

We multiply parentheses

63n+9+5

We add all the numbers together, and all the variables

63n+14

Back to the equation:

-(63n+14)



We get rid of parentheses

12n-63n-14+18=0

We add all the numbers together, and all the variables

-51n+4=0

We move all terms containing n to the left, all other terms to the right

-51n=-4

n=-4/-51

n=4/51

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