6(2n-2)-7(n-2)=32

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Solution for 6(2n-2)-7(n-2)=32 equation: 


Simplifying
6(2n + -2) + -7(n + -2) = 32

Reorder the terms:
6(-2 + 2n) + -7(n + -2) = 32
(-2 * 6 + 2n * 6) + -7(n + -2) = 32
(-12 + 12n) + -7(n + -2) = 32

Reorder the terms:
-12 + 12n + -7(-2 + n) = 32
-12 + 12n + (-2 * -7 + n * -7) = 32
-12 + 12n + (14 + -7n) = 32

Reorder the terms:
-12 + 14 + 12n + -7n = 32

Combine like terms: -12 + 14 = 2
2 + 12n + -7n = 32

Combine like terms: 12n + -7n = 5n
2 + 5n = 32

Solving
2 + 5n = 32

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 5n = 32 + -2

Combine like terms: 2 + -2 = 0
0 + 5n = 32 + -2
5n = 32 + -2

Combine like terms: 32 + -2 = 30
5n = 30

Divide each side by '5'.
n = 6

Simplifying
n = 6

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