6(2n-5)=-3(7-3n)+29

Solution for 6(2n-5)=-3(7-3n)+29 equation:

6(2n-5)=-3(7-3n)+29

We move all terms to the left:

6(2n-5)-(-3(7-3n)+29)=0

We add all the numbers together, and all the variables

6(2n-5)-(-3(-3n+7)+29)=0

We multiply parentheses

12n-(-3(-3n+7)+29)-30=0


We calculate terms in parentheses: -(-3(-3n+7)+29), so:

-3(-3n+7)+29

We multiply parentheses

9n-21+29

We add all the numbers together, and all the variables

9n+8

Back to the equation:

-(9n+8)


We get rid of parentheses

12n-9n-8-30=0

We add all the numbers together, and all the variables

3n-38=0

We move all terms containing n to the left, all other terms to the right

3n=38

n=38/3

n=12+2/3