6(2n-5)=-3(7-3n)=2

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Solution for 6(2n-5)=-3(7-3n)=2 equation: 



6(2n-5)=-3(7-3n)=2

We move all terms to the left:

6(2n-5)-(-3(7-3n))=0

We add all the numbers together, and all the variables

6(2n-5)-(-3(-3n+7))=0

We multiply parentheses

12n-(-3(-3n+7))-30=0



We calculate terms in parentheses: -(-3(-3n+7)), so:

-3(-3n+7)

We multiply parentheses

9n-21

Back to the equation:

-(9n-21)



We get rid of parentheses

12n-9n+21-30=0

We add all the numbers together, and all the variables

3n-9=0

We move all terms containing n to the left, all other terms to the right

3n=9

n=9/3

n=3

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