6(2n-5)=3(3n-4)-4

Solution for 6(2n-5)=3(3n-4)-4 equation:

6(2n-5)=3(3n-4)-4

We move all terms to the left:

6(2n-5)-(3(3n-4)-4)=0

We multiply parentheses

12n-(3(3n-4)-4)-30=0


We calculate terms in parentheses: -(3(3n-4)-4), so:

3(3n-4)-4

We multiply parentheses

9n-12-4

We add all the numbers together, and all the variables

9n-16

Back to the equation:

-(9n-16)


We get rid of parentheses

12n-9n+16-30=0

We add all the numbers together, and all the variables

3n-14=0

We move all terms containing n to the left, all other terms to the right

3n=14

n=14/3

n=4+2/3