6(2n-7)=22-4n

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Solution for 6(2n-7)=22-4n equation: 



6(2n-7)=22-4n

We move all terms to the left:

6(2n-7)-(22-4n)=0

We add all the numbers together, and all the variables

6(2n-7)-(-4n+22)=0

We multiply parentheses

12n-(-4n+22)-42=0

We get rid of parentheses

12n+4n-22-42=0

We add all the numbers together, and all the variables

16n-64=0

We move all terms containing n to the left, all other terms to the right

16n=64

n=64/16

n=4

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