6(2p+3)=(7p-22)

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Solution for 6(2p+3)=(7p-22) equation: 



6(2p+3)=(7p-22)

We move all terms to the left:

6(2p+3)-((7p-22))=0

We multiply parentheses

12p-((7p-22))+18=0



We calculate terms in parentheses: -((7p-22)), so:

(7p-22)

We get rid of parentheses

7p-22

Back to the equation:

-(7p-22)



We get rid of parentheses

12p-7p+22+18=0

We add all the numbers together, and all the variables

5p+40=0

We move all terms containing p to the left, all other terms to the right

5p=-40

p=-40/5

p=-8

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