6(2q+3)+4(q-2)=122

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Solution for 6(2q+3)+4(q-2)=122 equation:


Simplifying
6(2q + 3) + 4(q + -2) = 122

Reorder the terms:
6(3 + 2q) + 4(q + -2) = 122
(3 * 6 + 2q * 6) + 4(q + -2) = 122
(18 + 12q) + 4(q + -2) = 122

Reorder the terms:
18 + 12q + 4(-2 + q) = 122
18 + 12q + (-2 * 4 + q * 4) = 122
18 + 12q + (-8 + 4q) = 122

Reorder the terms:
18 + -8 + 12q + 4q = 122

Combine like terms: 18 + -8 = 10
10 + 12q + 4q = 122

Combine like terms: 12q + 4q = 16q
10 + 16q = 122

Solving
10 + 16q = 122

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 16q = 122 + -10

Combine like terms: 10 + -10 = 0
0 + 16q = 122 + -10
16q = 122 + -10

Combine like terms: 122 + -10 = 112
16q = 112

Divide each side by '16'.
q = 7

Simplifying
q = 7

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