6(2q+3)=17

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Solution for 6(2q+3)=17 equation:



6(2q+3)=17
We move all terms to the left:
6(2q+3)-(17)=0
We multiply parentheses
12q+18-17=0
We add all the numbers together, and all the variables
12q+1=0
We move all terms containing q to the left, all other terms to the right
12q=-1
q=-1/12
q=-1/12

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