6(2r+3)=42

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Solution for 6(2r+3)=42 equation: 



6(2r+3)=42

We move all terms to the left:

6(2r+3)-(42)=0

We multiply parentheses

12r+18-42=0

We add all the numbers together, and all the variables

12r-24=0

We move all terms containing r to the left, all other terms to the right

12r=24

r=24/12

r=2

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