6(2r-2)=-8r+40

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Solution for 6(2r-2)=-8r+40 equation: 



6(2r-2)=-8r+40

We move all terms to the left:

6(2r-2)-(-8r+40)=0

We multiply parentheses

12r-(-8r+40)-12=0

We get rid of parentheses

12r+8r-40-12=0

We add all the numbers together, and all the variables

20r-52=0

We move all terms containing r to the left, all other terms to the right

20r=52

r=52/20

r=2+3/5

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