6(2s+5)=27-4s

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Solution for 6(2s+5)=27-4s equation: 



6(2s+5)=27-4s

We move all terms to the left:

6(2s+5)-(27-4s)=0

We add all the numbers together, and all the variables

6(2s+5)-(-4s+27)=0

We multiply parentheses

12s-(-4s+27)+30=0

We get rid of parentheses

12s+4s-27+30=0

We add all the numbers together, and all the variables

16s+3=0

We move all terms containing s to the left, all other terms to the right

16s=-3

s=-3/16

s=-3/16

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