6(2t)-3=22t+12

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Solution for 6(2t)-3=22t+12 equation: 



6(2t)-3=22t+12

We move all terms to the left:

6(2t)-3-(22t+12)=0

We get rid of parentheses

62t-22t-12-3=0

We add all the numbers together, and all the variables

40t-15=0

We move all terms containing t to the left, all other terms to the right

40t=15

t=15/40

t=3/8

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