6(2t+2)=5(2t+4)

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Solution for 6(2t+2)=5(2t+4) equation: 



6(2t+2)=5(2t+4)

We move all terms to the left:

6(2t+2)-(5(2t+4))=0

We multiply parentheses

12t-(5(2t+4))+12=0



We calculate terms in parentheses: -(5(2t+4)), so:

5(2t+4)

We multiply parentheses

10t+20

Back to the equation:

-(10t+20)



We get rid of parentheses

12t-10t-20+12=0

We add all the numbers together, and all the variables

2t-8=0

We move all terms containing t to the left, all other terms to the right

2t=8

t=8/2

t=4

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