6(2t-4)=48

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Solution for 6(2t-4)=48 equation: 



6(2t-4)=48

We move all terms to the left:

6(2t-4)-(48)=0

We multiply parentheses

12t-24-48=0

We add all the numbers together, and all the variables

12t-72=0

We move all terms containing t to the left, all other terms to the right

12t=72

t=72/12

t=6

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