6(2t-5)=2(3t+3)

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Solution for 6(2t-5)=2(3t+3) equation: 



6(2t-5)=2(3t+3)

We move all terms to the left:

6(2t-5)-(2(3t+3))=0

We multiply parentheses

12t-(2(3t+3))-30=0



We calculate terms in parentheses: -(2(3t+3)), so:

2(3t+3)

We multiply parentheses

6t+6

Back to the equation:

-(6t+6)



We get rid of parentheses

12t-6t-6-30=0

We add all the numbers together, and all the variables

6t-36=0

We move all terms containing t to the left, all other terms to the right

6t=36

t=36/6

t=6

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