6(2u+9)-30=4(7u-2)

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Solution for 6(2u+9)-30=4(7u-2) equation: 



6(2u+9)-30=4(7u-2)

We move all terms to the left:

6(2u+9)-30-(4(7u-2))=0

We multiply parentheses

12u-(4(7u-2))+54-30=0



We calculate terms in parentheses: -(4(7u-2)), so:

4(7u-2)

We multiply parentheses

28u-8

Back to the equation:

-(28u-8)



We add all the numbers together, and all the variables

12u-(28u-8)+24=0

We get rid of parentheses

12u-28u+8+24=0

We add all the numbers together, and all the variables

-16u+32=0

We move all terms containing u to the left, all other terms to the right

-16u=-32

u=-32/-16

u=+2

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