6(2u-5)-1=2(2u+13)-1

Solution for 6(2u-5)-1=2(2u+13)-1 equation:

6(2u-5)-1=2(2u+13)-1

We move all terms to the left:

6(2u-5)-1-(2(2u+13)-1)=0

We multiply parentheses

12u-(2(2u+13)-1)-30-1=0


We calculate terms in parentheses: -(2(2u+13)-1), so:

2(2u+13)-1

We multiply parentheses

4u+26-1

We add all the numbers together, and all the variables

4u+25

Back to the equation:

-(4u+25)


We add all the numbers together, and all the variables

12u-(4u+25)-31=0

We get rid of parentheses

12u-4u-25-31=0

We add all the numbers together, and all the variables

8u-56=0

We move all terms containing u to the left, all other terms to the right

8u=56

u=56/8

u=7