6(2u-6)+2=4u-2+8u-32

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Solution for 6(2u-6)+2=4u-2+8u-32 equation: 


Simplifying
6(2u + -6) + 2 = 4u + -2 + 8u + -32

Reorder the terms:
6(-6 + 2u) + 2 = 4u + -2 + 8u + -32
(-6 * 6 + 2u * 6) + 2 = 4u + -2 + 8u + -32
(-36 + 12u) + 2 = 4u + -2 + 8u + -32

Reorder the terms:
-36 + 2 + 12u = 4u + -2 + 8u + -32

Combine like terms: -36 + 2 = -34
-34 + 12u = 4u + -2 + 8u + -32

Reorder the terms:
-34 + 12u = -2 + -32 + 4u + 8u

Combine like terms: -2 + -32 = -34
-34 + 12u = -34 + 4u + 8u

Combine like terms: 4u + 8u = 12u
-34 + 12u = -34 + 12u

Add '34' to each side of the equation.
-34 + 34 + 12u = -34 + 34 + 12u

Combine like terms: -34 + 34 = 0
0 + 12u = -34 + 34 + 12u
12u = -34 + 34 + 12u

Combine like terms: -34 + 34 = 0
12u = 0 + 12u
12u = 12u

Add '-12u' to each side of the equation.
12u + -12u = 12u + -12u

Combine like terms: 12u + -12u = 0
0 = 12u + -12u

Combine like terms: 12u + -12u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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