6(2v+1)=4(v+3)

Solution for 6(2v+1)=4(v+3) equation:

Simplifying
6(2v + 1) = 4(v + 3)

Reorder the terms:
6(1 + 2v) = 4(v + 3)
(1 * 6 + 2v * 6) = 4(v + 3)
(6 + 12v) = 4(v + 3)

Reorder the terms:
6 + 12v = 4(3 + v)
6 + 12v = (3 * 4 + v * 4)
6 + 12v = (12 + 4v)

Solving
6 + 12v = 12 + 4v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-4v' to each side of the equation.
6 + 12v + -4v = 12 + 4v + -4v

Combine like terms: 12v + -4v = 8v
6 + 8v = 12 + 4v + -4v

Combine like terms: 4v + -4v = 0
6 + 8v = 12 + 0
6 + 8v = 12

Add '-6' to each side of the equation.
6 + -6 + 8v = 12 + -6

Combine like terms: 6 + -6 = 0
0 + 8v = 12 + -6
8v = 12 + -6

Combine like terms: 12 + -6 = 6
8v = 6

Divide each side by '8'.
v = 0.75

Simplifying
v = 0.75