6(2v+2)+3v=6(v-5)+2v

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Solution for 6(2v+2)+3v=6(v-5)+2v equation: 



6(2v+2)+3v=6(v-5)+2v

We move all terms to the left:

6(2v+2)+3v-(6(v-5)+2v)=0

We add all the numbers together, and all the variables

3v+6(2v+2)-(6(v-5)+2v)=0

We multiply parentheses

3v+12v-(6(v-5)+2v)+12=0



We calculate terms in parentheses: -(6(v-5)+2v), so:

6(v-5)+2v

We add all the numbers together, and all the variables

2v+6(v-5)

We multiply parentheses

2v+6v-30

We add all the numbers together, and all the variables

8v-30

Back to the equation:

-(8v-30)



We add all the numbers together, and all the variables

15v-(8v-30)+12=0

We get rid of parentheses

15v-8v+30+12=0

We add all the numbers together, and all the variables

7v+42=0

We move all terms containing v to the left, all other terms to the right

7v=-42

v=-42/7

v=-6

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