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6(2x+1)-2(x+2)=2(5x+1)
We move all terms to the left:
6(2x+1)-2(x+2)-(2(5x+1))=0
We multiply parentheses
12x-2x-(2(5x+1))+6-4=0
We calculate terms in parentheses: -(2(5x+1)), so:We add all the numbers together, and all the variables
2(5x+1)
We multiply parentheses
10x+2
Back to the equation:
-(10x+2)
10x-(10x+2)+2=0
We get rid of parentheses
10x-10x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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