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6(2x+1)-3(x-2)=9x+20
We move all terms to the left:
6(2x+1)-3(x-2)-(9x+20)=0
We multiply parentheses
12x-3x-(9x+20)+6+6=0
We get rid of parentheses
12x-3x-9x-20+6+6=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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