6(2x+1)-8=5(1+2x)-9

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Solution for 6(2x+1)-8=5(1+2x)-9 equation: 



6(2x+1)-8=5(1+2x)-9

We move all terms to the left:

6(2x+1)-8-(5(1+2x)-9)=0

We add all the numbers together, and all the variables

6(2x+1)-(5(2x+1)-9)-8=0

We multiply parentheses

12x-(5(2x+1)-9)+6-8=0



We calculate terms in parentheses: -(5(2x+1)-9), so:

5(2x+1)-9

We multiply parentheses

10x+5-9

We add all the numbers together, and all the variables

10x-4

Back to the equation:

-(10x-4)



We add all the numbers together, and all the variables

12x-(10x-4)-2=0

We get rid of parentheses

12x-10x+4-2=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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