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6(2x+1)=(3x-4)
We move all terms to the left:
6(2x+1)-((3x-4))=0
We multiply parentheses
12x-((3x-4))+6=0
We calculate terms in parentheses: -((3x-4)), so:We get rid of parentheses
(3x-4)
We get rid of parentheses
3x-4
Back to the equation:
-(3x-4)
12x-3x+4+6=0
We add all the numbers together, and all the variables
9x+10=0
We move all terms containing x to the left, all other terms to the right
9x=-10
x=-10/9
x=-1+1/9
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