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6(2x+1)=2(2x-1)
We move all terms to the left:
6(2x+1)-(2(2x-1))=0
We multiply parentheses
12x-(2(2x-1))+6=0
We calculate terms in parentheses: -(2(2x-1)), so:We get rid of parentheses
2(2x-1)
We multiply parentheses
4x-2
Back to the equation:
-(4x-2)
12x-4x+2+6=0
We add all the numbers together, and all the variables
8x+8=0
We move all terms containing x to the left, all other terms to the right
8x=-8
x=-8/8
x=-1
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