6(2x+1)=3(-2x-10)

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Solution for 6(2x+1)=3(-2x-10) equation: 



6(2x+1)=3(-2x-10)

We move all terms to the left:

6(2x+1)-(3(-2x-10))=0

We multiply parentheses

12x-(3(-2x-10))+6=0



We calculate terms in parentheses: -(3(-2x-10)), so:

3(-2x-10)

We multiply parentheses

-6x-30

Back to the equation:

-(-6x-30)



We get rid of parentheses

12x+6x+30+6=0

We add all the numbers together, and all the variables

18x+36=0

We move all terms containing x to the left, all other terms to the right

18x=-36

x=-36/18

x=-2

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